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0=-5x^2+18x-13.1
We move all terms to the left:
0-(-5x^2+18x-13.1)=0
We add all the numbers together, and all the variables
-(-5x^2+18x-13.1)=0
We get rid of parentheses
5x^2-18x+13.1=0
a = 5; b = -18; c = +13.1;
Δ = b2-4ac
Δ = -182-4·5·13.1
Δ = 62
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-\sqrt{62}}{2*5}=\frac{18-\sqrt{62}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+\sqrt{62}}{2*5}=\frac{18+\sqrt{62}}{10} $
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